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高效Python扫雷游戏:自动化体验揭秘

发布时间:2024-10-23浏览:92

自动扫雷一般分为两种,一种是读取内存数据,而另一种是通过分析图片获得数据,并通过模拟鼠标操作,这里我用的是第二种方式。

一、准备工作

1.扫雷游戏

我是win10,没有默认的扫雷,所以去扫雷网下载

http://www.saolei.net/BBS/

2.python 3

我的版本是 python 3.6.1

3.python的第三方库

win32api,win32gui,win32con,Pillow,numpy,opencv可通过 pip install --upgrade SomePackage 来进行安装注意:有的版本是下载pywin32,但是有的要把pywin32升级到最高并自动下载了pypiwin32,具体情况每个python版本可能都略有不同

我给出我的第三方库和版本仅供参考

二、关键代码组成

1.找到游戏窗口与坐标

#扫雷游戏窗口class_name = "TMain"title_name = "Minesweeper Arbiter "hwnd = win32gui.FindWindow(class_name, title_name) #窗口坐标left = 0top = 0right = 0bottom = 0 if hwnd: print("找到窗口") left, top, right, bottom = win32gui.GetWindowRect(hwnd) #win32gui.SetForegroundWindow(hwnd) print("窗口坐标:") print(str(left)+' '+str(right)+' '+str(top)+' '+str(bottom))else: print("未找到窗口")

2.锁定并抓取雷区图像

3.各图像的RGBA值

#数字1-8 周围雷数#0 未被打开#ed 被打开 空白#hongqi 红旗#boom 普通雷#boom_red 踩中的雷rgba_ed = [(225, (192, 192, 192)), (31, (128, 128, 128))]rgba_hongqi = [(54, (255, 255, 255)), (17, (255, 0, 0)), (109, (192, 192, 192)), (54, (128, 128, 128)), (22, (0, 0, 0))]rgba_0 = [(54, (255, 255, 255)), (148, (192, 192, 192)), (54, (128, 128, 128))]rgba_1 = [(185, (192, 192, 192)), (31, (128, 128, 128)), (40, (0, 0, 255))]rgba_2 = [(160, (192, 192, 192)), (31, (128, 128, 128)), (65, (0, 128, 0))]rgba_3 = [(62, (255, 0, 0)), (163, (192, 192, 192)), (31, (128, 128, 128))]rgba_4 = [(169, (192, 192, 192)), (31, (128, 128, 128)), (56, (0, 0, 128))]rgba_5 = [(70, (128, 0, 0)), (155, (192, 192, 192)), (31, (128, 128, 128))]rgba_6 = [(153, (192, 192, 192)), (31, (128, 128, 128)), (72, (0, 128, 128))]rgba_8 = [(149, (192, 192, 192)), (107, (128, 128, 128))]rgba_boom = [(4, (255, 255, 255)), (144, (192, 192, 192)), (31, (128, 128, 128)), (77, (0, 0, 0))]rgba_boom_red = [(4, (255, 255, 255)), (144, (255, 0, 0)), (31, (128, 128, 128)), (77, (0, 0, 0))]

4.扫描雷区图像保存至一个二维数组map

#扫描雷区图像def showmap(): img = ImageGrab.grab().crop(rect) for y in range(blocks_y): for x in range(blocks_x): this_image = img.crop((x * block_width, y * block_height, (x + 1) * block_width, (y + 1) * block_height)) if this_image.getcolors() == rgba_0: map[y][x] = 0 elif this_image.getcolors() == rgba_1: map[y][x] = 1 elif this_image.getcolors() == rgba_2: map[y][x] = 2 elif this_image.getcolors() == rgba_3: map[y][x] = 3 elif this_image.getcolors() == rgba_4: map[y][x] = 4 elif this_image.getcolors() == rgba_5: map[y][x] = 5 elif this_image.getcolors() == rgba_6: map[y][x] = 6 elif this_image.getcolors() == rgba_8: map[y][x] = 8 elif this_image.getcolors() == rgba_ed: map[y][x] = -1 elif this_image.getcolors() == rgba_hongqi: map[y][x] = -4 elif this_image.getcolors() == rgba_boom or this_image.getcolors() == rgba_boom_red: global gameover gameover = 1 break #sys.exit(0) else: print("无法识别图像") print("坐标") print((y,x)) print("颜色") print(this_image.getcolors()) sys.exit(0) #print(map)

5.扫雷算法

这里我采用的最基础的算法

1.首先点出一个点

2.扫描所有数字,如果周围空白+插旗==数字,则空白均有雷,右键点击空白插旗

3.扫描所有数字,如果周围插旗==数字,则空白均没有雷,左键点击空白

4.循环2、3,如果没有符合条件的,则随机点击一个白块

这个算法在初级和中级通过率都不错,但是在高级成功率惨不忍睹,主要是没有考虑逻辑组合以及白块是雷的概率问题,可以对这两个点进行改进,提高成功率

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